Question

A fixed 16.1-cm-diameter wire coil is perpendicular to a magnetic field 0.53 T pointing up. In 0.23 s , the field is changed to 0.19 T pointing down. Part APart complete What is the average induced emf in the coil?

Answer 1

Average induced emf will be equal to 0.00156 volt

Step-by-step explanation:

We have given diameter of the wire d = 16.1 cm

So radius
`r=(16.1)/(2)=8.05cm=0.08m`

Cross sectional area of the wire
`A=\pi r^2=3.14* 0.08^2=0.02m^2`

Magnetic field is changing from 0.53 T to 0.19 T

So change in magnetic field dB = 0.19-0.53 = -0.34 T

Time taken to change in magnetic field dt = 0.23 sec

Induced emf is given by
`e=(-d\Phi )/(dt)=-A(dB)/(dt)=-0.02* (0.34)/(0.23)=0.00156volt`

So average induced emf will be equal to 0.00156 volt