Question

The pupil of a cat's eye narrows to a vertical slit of width 0.540 mm in daylight. Assume the average wavelength of the light is 471 nm. What is the angular resolution for horizontally separated mice

Answer 1

Resolution of the light will be equal to
`872.22* 10^(-6)radian`

Step-by-step explanation:

We have given a pupil of cat width of the slit d = 0.540 mm =
`0.540* 10^(-3)m`

Average wavelength of the light
`\lambda =471nm=471* 10^(-9)m`

We have to find the angular resolution for horizontally separated mice

Angular resolution is given by
`\Theta =(\lambda )/(d)=(471* 10^(-9))/(0.540* 10^(-3))=872.22* 10^(-6)radian`

So resolution of the light will be equal to
`872.22* 10^(-6)radian`