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Which of the following compounds would be consistent with a compound showing an M with an m/z ratio of 43 in a mass spectrometer? Select all that apply.

a. CH3CH2OH
b. CH3CH2NH2
c. propane
d. propene
e. None of the choices are correct.

User HAdes
by
5.1k points

1 Answer

4 votes

Answer:

The option (e) None of the choice are correct.

Step-by-step explanation:

To find
(m)/(z) ratio in mass spectrometer,

We start calculating from the first option

(a)


CH_(3)- CH_(2)- OH

We know mass of carbon
m= 12 and atomic number of carbon
Z = 6

After calculating we come up with,


(m)/(z) = 46

Therefore option (a) is incorrect.

(b)


CH_(3) -CH_(2)- NH_(2)

After calculating we come up with,


(m)/(z) = 45

Therefore option (b) is incorrect.

(c)


CH_(3)- CH_(2)-CH_(3)


(m)/(z) = 44

Therefore option (c) is incorrect.

(d)


CH_(3)- CH=CH_(2)


(m)/(z) = 42

Therefore option (d) is incorrect.

Therefore, the option (e) is correct for this problem

User Alexey Kosov
by
4.1k points