For this case we have that by definition, the area of a rectangle is given by:
![A = w * l](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9nq0wpi12rveih587g99nnp6zz47o7x9da.png)
Where:
w: Is the width of the rectangle
l: is the length of the rectangle
According to the data of the statement we have:
![A = 81-x ^ 2\\w = 9-x](https://img.qammunity.org/2021/formulas/mathematics/high-school/lmveo6fkcntvqvjbb31za80bvmwyr21erw.png)
So, the length is given by:
![l = \frac {A} {w}\\l = \frac {81-x ^ 2} {9-x}](https://img.qammunity.org/2021/formulas/mathematics/high-school/lc6y0mfruy11544y648qves1gjj11f5t34.png)
We factor the numerator:
![l = \frac {(9 + x) (9-x)} {9-x}](https://img.qammunity.org/2021/formulas/mathematics/high-school/4bm3pluhmmt7otn3dsw7u1az3qbcp1lwkn.png)
We simplify:
![l = 9 + x](https://img.qammunity.org/2021/formulas/mathematics/high-school/il9vv90imnh4p4ihk57u3pidsut9ncg7ww.png)
So, the length is
![9 + x](https://img.qammunity.org/2021/formulas/mathematics/high-school/qolt4sq069jqbmytn5y4idm8v9qfqueypr.png)
Answer:
![9 + x](https://img.qammunity.org/2021/formulas/mathematics/high-school/qolt4sq069jqbmytn5y4idm8v9qfqueypr.png)