Question

A stainless steel tube with an outside diameter of 54 mm and a wall thickness of 5 mm is used as a compression member. If the axial normal stress in the member must be limited to 190 MPa, determine the maximum load P that the member can support.

Answer 1

Answer:146.26 kN

Step-by-step explanation:

Given

Outside diameter of tube
`d_o=54\ mm`

thickness of tube
`t=5\ mm`

therefore inner diameter
`d_i=54-2* 5`

`d_i=44\ mm`

Cross-section of tube
`A=(\pi )/(4)(D_o^2-d_i^2)`

`A=(\pi )/(4)* 980`

`A=245\pi mm^2`

Stress developed must be less than the limited value

thus
`(P)/(A)\leq \sigma`

`P\leq \sigma A`

Maximum value of
`P=\sigma * A`

`P=190* 245* \pi`

`P=146.26\ kN`