Use the following to answer question 39: The average score of 100 students taking a statistics final was 70 with a standard deviation of 7. Assuming a normal distribution, what …

Question

asked Jun 3, 2021 134k views

1 Answer

Anbanm · Answer 1 · 2021-06-08T06:31:40+0000

Answer:

The probability of students scored less than 60 = .0768

Explanation:

Given -

Mean score
$(\\u )$ = 70

standard deviation
$(\sigma )$ = 7

Let X be the score of students

the probability that students scored less than 60 =

P(X< 60) =
$P((X - \\u )/(\sigma)< (60 - 70)/(7))$

=
P(z < (60 - 70)/(7)) put[ Z=
$(X - \\u )/(\sigma)$ ]

=
P(z < -1.428) using z table

= .0768