Question

A circle is shown. Secants R S and R T intersect at point R outside of the circle. Secant R S intersects the circle at point U. Secant R T intersects the circle at point V. The length of R U is 6, the length of U S is 10, and the length of R V is 8.

If secant segments SR and TR intersect at point R, find the length of VT.

Start by relating the secants and segments theorem to this diagram:

(RS)() = ()(RV)

Substitute values from the diagram into the equation:

(16)() = ()(8)

Solve for VT:

VT =

Answer 1

(RS) [(RU)] = [(RT)] (RV)

(16) [(6)] = [(8+VT)] (8)

VT = [4]

Explanation:

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Answer 2

Everything in -> [x]

(RS) [(RU)] = [(RT)] (RV)

(16) [(6)] = [(8+VT)] (8)

VT = [4]

Explanation:

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