Question

Say you want to make a sling by swinging a mass M of 1.7 kg in a horizontal circle of radius 0.048 m, using a string of length 0.048 m. You wish the mass to have a kinetic energy of 14.0 Joules when released. How strong will the string need to be

Answer 1

Tension in the string is equal to 58.33 N ( this will be the strength of the string )

Step-by-step explanation:

We have given mass m = 1.7 kg

radius of the circle r = 0.48 m
`F=(mv^2)/(r)=(1.7* 4.05^2)/(0.48)=58.33N`

Kinetic energy is given 14 J

Kinetic energy is equal to
`KE=(1)/(2)mv^2`

So
`(1)/(2)* 1.7* v^2=14`

`v^2=16.47`

v = 4.05 m/sec

Centripetal force is equal to
`F=(mv^2)/(r)=(1.7* 4.05^2)/(0.48)=58.33N`

So tension in the string will be equal to 58.33 N ( this will be the strength of the string )