Question

As a diligent physics student, you carry out physics experiments at every opportunity. At this opportunity, you carry a 1.05 m 1.05 m long rod as you jog at 3.27 m/s 3.27 m/s , holding the rod perpendicular to your direction of motion. What is the strength of the magnetic field that is perpendicular to both the rod and your direction of motion and that induces an EMF of 0.275 mV 0.275 mV across the rod? Express the answer in milliteslas.

Answer 1

The strength of the magnetic field is 0.08 mT

Step-by-step explanation:

Given:

Length of rod
`l = 1.05` m

Velocity of rod
`v = 3.27`
`(m)/(s)`

Induced emf
`\epsilon = 0.275 * 10^(-3)` V

According to the faraday's law

We know that the induced emf of rod is given by,

`\epsilon = Blv`

Where
`B =` magnetic field

For finding the magnetic field,

`B = (\epsilon )/(lv)`

`B = (0.275 * 10^(-3) )/(1.05 * 3.27)`

`B = 0.08 * 10^(-3)`

`B = 0.08` mT

Therefore, the strength of the magnetic field is 0.08 mT