Answer:
Q = 1569 j
Step-by-step explanation:
Given data:
Mass of water = 5.00 g
Initial temperature = 25.0°C
Final temperature = 100°C
Cp = 4.184 j/g.°C
Energy needed = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 100°C - 25°C
ΔT = 75°C
Q = 5 g× 4.184 j/g.°C×75°C
Q = 1569 j