Question

According to VSEPR theory, the molecule PF6- has how many regions of electron density around the central atom (how many electron groups?) (enter a number from 1 to 6) PF6- will have (linear, trigonal planar, tetrahedral, trigonal pyramidal, bent, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal, square planar) electronic geometry, and (linear, trigonal planar, tetrahedral, trigonal pyramidal, bent, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal, square planar) molecular geometry.

Answer 1

Answer : The electronic geometry and the molecular geometry of the molecule will be octahedral.

Explanation :

Formula used :

`\text{Number of electron pair}=(1)/(2)[V+N-C+A]`

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

The given molecule is,
`PF_6^-`

`\text{Number of electrons}=(1)/(2)* [5+6+1]=6`

The number of electron pair are 6 that means the hybridization will be
`sp^3d^2` and the electronic geometry and the molecular geometry of the molecule will be octahedral.