Question

Determine the absolute pressure on the bottom of a swimming pool 30.0 m by 8.9 m whose uniform depth is 1.9 m . Express your answer using two significant figures. P = nothing N/m2 Request Answer Part B Determine the total force on the bottom of a swimming pool. Express your answer using two significant figures. F = nothing N Request Answer Part C What will be the pressure against the side of the pool near the bottom? Express your answer using two significant figures. P = nothing N/m2 Request Answer Provide Feedback

Answer 1

A)P = 1.2 × 10⁵Pa

B)F = 3.2 × 10⁷N

C) P = 1.2 × 10⁵Pa

Step-by-step explanation:

Part A)

The relative pressure at the bottom of a column of fluid is given by

`p_r = \rho g h`

where

`\rho` is the fluid density

g is the gravitational acceleration

h is the height of the column of fluid

At the bottom of the swimming pool, h=1.9 m, and the water density is

`\rho` = 1000 kg/m^3, therefore the relative pressure is

`p_r = (1000 kg/m^3)(9.81 m/s^2)(1.9 m)=1.86 \cdot 10^4 Pa`

To find the absolute pressure, we must add to this the atmospheric pressure,
`p_a` :

`p= p_r + p_a\\= 1.86 \cdot 10^4 Pa + 1.01 \cdot 10^5 Pa \\=1.2 * 10^5 Pa`

part B

Total force acting on the bottom

force = pressure * area

area of pool = 30.0 m × 8.9 m

= 267m²

Force F =

1.2 × 10⁵ * 267m² N

= 32040000 N

F = 3.2 × 10⁷N

Part C

The pressure acting on the side wall will be

now the pressure at the side of the pool at the bottom is simply equal to absolute pressure as they are at same level

P = 1.2 × 10⁵

Answer 2

Absolute pressure=density*g*h

Absolute pressure=1000*9.8*1.9

Absolute pressure=18260 N/m^2

Force on the bottom=PA=18260*(30)(8.9)=4971540 N