Question

An office window has dimensions 3.1 m by 2.1 m. As a result of the passage of a storm, the outside air pressure drops to 0.954 atm, but inside the pressure is held at 1.0 atm. What net force pushes out on the window

Answer 1

Net forces which pushes the window is 30342.78 N.

Step-by-step explanation:

Given:

Dimension of the office window.

Length of the window =
`3.1` m

Width of the window =
`2.1` m

Area of the window =
`(3.1* 2.1) = 6.51\ m^2`

Difference in air pressure = Inside pressure - Outside pressure

=
`(1.0-0.954)` atm =
`0.046` atm

Conversion of the pressure in its SI unit.

⇒
`1` atm =
`101325` Pa

⇒
`0.046` atm =
`0.046* 101325 =4660.95` Pa

We have to find the net force.

We know,

⇒ Pressure = Force/Area

⇒
`Pressure=(Force )/(Area)`

⇒
`Force =Pressure* Area`

⇒ Plugging the values.

⇒
`Force =4660.95* 6.51`

⇒
`Force=30342.78` Newton (N)

So,

The net forces which pushes the window is 30342.78 N.