Question

Consider the solubilities of a particular solute at two different temperatures. Temperature ( ∘ C ) Solubility ( g / 100 g H 2 O ) 20.0 32.2 30.0 70.2 Suppose a saturated solution of this solute was made using 56.0 g H 2 O at 20.0 °C. How much more solute can be added if the temperature is increased to 30.0 ∘ C? mass:

Answer 1

21.28 grams solute can be added if the temperature is increased to 30.0°C.

Step-by-step explanation:

Solubility of solute at 20°C = 32.2 g/100 grams of water

Solute soluble in 1 gram of water =
`(32.2)/(100)g=0.322 g`

Mass of solute in soluble in 56.0 grams of water:

`0.322* 56.0=18.032 g`

Solubility of solute at 30°C = 70.2g/100 grams of water

Solute soluble in 1 gram of water =
`(70.2)/(100)g=0.702 g`

Mass of solute in soluble in 56.0 grams of water:

`0.702 * 56.0=39.312 g`

If the temperature of saturated solution of this solute using 56.0 g of water at 20.0 °C raised to 30.0°C

Mass of solute in soluble in 56.0 grams of water 20.0°C = 18.032 g

Mass of solute in soluble in 56.0 grams of water at 30.0°C = 39.312 g

Mass of of solute added If the temperature of the saturated solution increased to 30.0°C:

39.312 g - 18.032 g = 21.28 g

21.28 grams solute can be added if the temperature is increased to 30.0°C.