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A radioactive substance decays according to the following function, where yo is the initial amount present, and y is the amount present at time t (in days).

y= y_o e^0.072t.

Find the half-life of this substance. Do not round any intermediate computations, and round your answer to the nearest tenth. days

User Luoluo
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1 Answer

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Answer:


t_(1/2) \approx 9.6\,days

Explanation:

The time constant of the radioactive constant is:


\tau = (1)/(0.072)\,days


\tau = 13.889\,days

The half-life of the substance is:


t_(1/2) = \tau \cdot \ln 2


t_(1/2) = (13.889\,days)\cdot \ln 2


t_(1/2) \approx 9.6\,days

User Deltree
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