Question

Calculate the magnitude of the magnetic force on a 270 m length of wire stretched between two towers and carrying a 150 A current. The Earth's magnetic field of 4.0×10−5 T makes an angle of 80 ∘ with the wire

Answer 1

Force on the wire is equal to 15.95 N

Step-by-step explanation:

We have given length of the wire l = 270 m

Current flowing in the wire i = 150 A

Magnetic field
`B=4* 10^(-5)T`

Angle between magnetic field and wire
`\Theta =80^(\circ)`

We have to find the force on the wire

Force on current carrying conductor is equal to
`F=IBlsin\Theta`

So
`F=150* 4* 10^(-5)* 270* sin80^(\circ)=15.95N`

So force on the wire is equal to 15.95 N