Question

G(x)=x^2-10x+24 if graphed on a coordinate plane where would it cross the x axis

Answer 1

Answer: x^2-10x+24 crosses the x-axis at (4,0) and (6,0)

Step-by-step explanation: (4)^2-10(4)+24 = 0, (6)^2-10(6)+24 = 0.