Question

Tina rides the bus to school, Theo bikes to school, and Tony walks to school. Their probabilities of being the first one to school are as follows:

\text{P(Tina is first}) = 0.05P(Tina is first)=0.05start text, P, left parenthesis, T, i, n, a, space, i, s, space, f, i, r, s, t, end text, right parenthesis, equals, 0, point, 05
\text{P(Theo is first}) = 85\%P(Theo is first)=85%start text, P, left parenthesis, T, h, e, o, space, i, s, space, f, i, r, s, t, end text, right parenthesis, equals, 85, percent
\text{P(Tony is first}) = \dfrac{1}{10}P(Tony is first)=
10
1
​

Answer 1

Tina is first

Tony is first

Theo is first

Explanation:

Events with greater probability are more likely.

Let's put the probabilities in decimal form.

P(Tina is first) = 0.05

P(Theo is first) = %85 = 0.85

P(Tony is first) = 1/10 = 0.1

0.05 < 0.1 < 0.85

The events are listed below from least to most likely.

Tina is first, Tony is first, Theo is first

hope it helps

Answer 2

Tina is first

Tony is first

Theo is first

Explanation: