Question

What is a/8 - 7(3) = 4a - 78(b)

solve for b pls

Answer 1

b = (31a + 168)/624

Explanation:

a/8 - 7(3) = 4a - 78(b)

78b = 4a - a/8 + 21

78b = (32-1)a/8 + 21

78b = (31a + 21(8))/8

78b = (31a + 168)/8

b = (31a + 168)/8 × 1/78

b = (31a + 168)/624

Answer 2

31a/624 +7/26 = b

Explanation:

a/8 - 7(3) = 4a - 78(b)

Multiply

a/8 - 21 =4a -78b

Multiply each side by 8 to get rid of the fractions

8(a/8 - 21) =8(4a -78b)

a - 168 = 32a -624b

Subtract 32a from each side

a -32a -168 = 32a -32a -624b

-31a -168 = -624b

Divide each side by -624

(-31a -168)/-624 = -624b/-624

(31a+168)/624 = b

31a/624 +7/26 = b