Question

slader A baseball player slides to a stop on level ground. Using energy consideration, calculate the distance the 65 kg baseball player slides, given his initial speed is 6 m/s and the force of friction against him is a constant 450N.

Answer 1

The 65 kg baseball player slides a distance of 5.2 meters before coming to a stop, calculated using kinetic energy and the work done by friction.

Step-by-step explanation:

To calculate the distance the 65 kg baseball player slides using energy considerations, we start by noting that the work done by friction is equal to the loss in kinetic energy as the player comes to a stop. The kinetic energy (KE) of the player can be calculated using the formula KE = (1/2)mv², where m is mass and v is velocity. Since the force of friction (f) is constant, the work (W) done by friction is W = fd, with d being the distance over which the friction acts.

Setting the initial kinetic energy equal to the work done by friction, we get:

(1/2)mv² = fd

Inserting the given values, we have:

(1/2)(65 kg)(6 m/s)² = (450 N)d

Upon calculating, we find:

d = (1/2)(65 kg)(6 m/s)² / (450 N)

d = 5.2 meters

Therefore, the baseball player slides a distance of 5.2 meters before coming to a stop.

Answer 2

2.6 m

Step-by-step explanation:

From work energy theorem we deduce that

`0.5mv^(2)=fd`

The kinetic energy equals to the work dine against friction energy.

Where m represent mass, v is the velocity, f is the frictional force and d is unknown distance that the player slides.

Making d the subject of the formula then
`d=\frac {mv^(2)}{2f}`

Then by substituting 450N for f, 65 kg for m and 6 m/s for v we obtain

`d=\frac {65*6^(2)}{2*450}=2.6m`