Question

An electron is placed in a magnetic field that is directed along a z axis. The energy difference between parallel and antiparallel alignments of the z component of the electron's spin magnetic moment with is 7.50 × 10-25 J. What is the magnitude of ?

Answer 1

B = 0.0404 т

Step-by-step explanation:

Given

ΔE = 7.50 x 10⁻²⁵ J

μb = 927.4 x 10⁻²⁶ J/т

ΔE = 2 * μb * B

B = ΔE / 2 μb

B = 7.50 x 10⁻²⁵ / 2 * 927.4 x 10⁻²⁶

B = 7.50 / 1854.8 x 10⁻²⁵⁻⁽⁻²⁶⁾

B = 0.00404 x 10¹

B = 0.0404 т