Question

Find the perimeter of the shape given length = x^2+4 and the width = 3x-4.Explain how you found your answer to problem .

Answer 1

`2x^(2)+6x`

Explanation:

Perimeter is the distance all round a figure. Given length and width only, then this shale is likely to be a triangle. For a triangle, the area is given by

P=2(l+w)

Where l is the length and w is width.

Substituting w with 3x-4 and l with
`x^(2)+4`

then

`P=2( x^(2)+4 +3x-4)=2( x^(2)+3x)=2x^(2)+6x`

Therefore, perimeter is
`2x^(2)+6x`