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What was the initial reactant concentration for the reaction described in part a?.

User Zaha
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Answer:

The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line, y = mx + b. Part A The reactant concentration in a zero-order reaction was 0.100 M after 100 s and 1.50x10-2 M after 360 s. What is the rate constant for this reaction? Order 0 1 | 2 Integrated Rate Law Graph [A] =- kt +[A]o [A] vs. t In[A] = -kt + In[A]o In[A] vs. t = kt + Á A vs. t Slope -k -k k Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash. ► View Available Hint(s) koth = 3.27x10-4 M S Submi Previous Answers Correct Important: If you use this answer in later parts, use the full unrounded value in your calculations.

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User Suraj Shourie
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