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The manager at the local auto shop has found that the probability that a car brought into the shop requires an oil change is 0.83​, the probability that a car brought into the shop requires brake repair is 0.17​, and the probability that a car requires both an oil change and brake repair is 0.15. For a car brought into the​ shop, determine the probability that the car will require an oil change or brake repair.

1 Answer

6 votes

Answer:

0.85

Explanation:

Given two events A and B, the probability that either A or B occurs is given by:


p(A\cup B) = p(A)+p(B)-p(A\cap B)

where


p(A) the probability that A occurs


p(B) is the probability that B occurs


p(A\cap B) is the probability that both A and B occur at the same time

In this problem, we know the following facts:


p(o) = 0.83 is the probability that the car requires an oil change


p(b)=0.17 is the probability that the car requires a brake repair


p(o\cap b) = 0.15 is the probability that the car requires both an oil change and brake repair

Therefore, the probability that either o (car requiring oil change) or b (car requiring brake repait) occur is:


p(o\cup b)=p(o)+p(b)-p(o\cap b)=0.83+0.17-0.15 = 0.85

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