Question

A portable x-ray unit has a step-up transformer. The 120 V input is transformed to the 100 kV output needed by the x-ray tube. The primary has 73 loops and draws a current of 14.1 A when in use. What is the number of loops in the secondary

Answer 1

60833 loops

Step-by-step explanation:

Given parameters:

Input voltage = 120V

Output voltage = 100kV

Primary loops = 73 loops

Current = 14.1A

Unknown:

Number of loops in the secondary coil = ?

Solution:

A step up transformer of this nature increases the output voltage. Here, the voltage is raised on the output side.

One thing about a transformer is that the output and input power are always the same.

To find the number of loops in the secondary coil;

`(N_(p) )/(N_(s) ) = (V_(p) )/(V_(s) )`

Where N is the number of loops and V is the voltage

s and p are the secondary and primary parts

Note: 100kV = 100000V

Now input the parameters;

`(73)/(N_(s) ) = (120)/(100000)`

120N
`_(s)` = 73 x 100000

N
`_(s)` = 60833 loops