Question

What is the solubility of MgCO₃ in a solution that contains 0.080 M Mg²⁺ ions? (Ksp of MgCO₃ is 3.5 × 10⁻⁸)

Answer 1

Answer: 4.4 x 10^-7

Step-by-step explanation:

The dissociation equation for this reaction is:

MgCO3 (s) → Mg+2 (aq) + CO3-2 (aq)

`\text { So, } k_(s p)=(x+0.08) x` (Here 0.08 >>> x )

`\begin{aligned}\Rightarrow 3.5 * 10^(-8) &=0.08 * x \\\Rightarrow x &=(3.5)/(0.08) * 10^(-8) \\&=4.37 * 10^(-7) \\\Rightarrow x & \approx 4.4 * 10^(-7) \mathrm{~M}\end{aligned}`

So the solubility MgCO₃ in a solution that containing 0.080 M Mg²⁺ is 4.4 x 10^-7