Question

Urgent !! Convert the following equation to logarithmic or exponential form:

log subscript 49 left parenthesis 7 right parenthesis equals 1 half


Your answer:

49 to the power of 7 equals 1 half


7 to the power of 49 equals 1 half

open parentheses 1 half close parentheses to the power of 7 equals 49

49 to the power of 1 half end exponent equals 7

Answer 1

The given equation is log49(7) = 1/2. To convert it to exponential form, we can write it as 49^(1/2) = 7.

Step-by-step explanation:

The given equation is:

log49(7) = 1/2

To convert this equation to exponential form, we need to remember that logarithms and exponentials are inverse functions. Therefore, we can write the equation as:

491/2 = 7

Hence, the exponential form of the given equation is 49 raised to the power of 1/2 equals 7.

Answer 2

The exponential form is 49 to the power of one-half equals 7 ⇒ 4th answer

Step-by-step explanation:

The exponential equation of
`log_(b)(m)=n` is
`b^(n)=m` , where b is the base, n is the exponent of b and m is the value of
`b^(n)`

Ex: If
`log_(3)(81)=4` , that means b = 3 , n = 4 and m = 81, then its exponential form is
`3^(4)=81`

Now let us solve the question

∵ The equation is
`log_(49)(7)=(1)/(2)`

∴ The base is 49

∴ The exponent is
`(1)/(2)`

∴ The answer is 7

- Substitute them in the form of the exponential form

∴ The exponential form is
`(49)^{(1)/(2)}=7`

The exponential form is 49 to the power of one-half equals 7