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Find all of the eigenvalues λ of the matrix A. (Hint: Use the method of Example 4.5 of finding the solutions to the equation 0 = det(A − λI). Enter your answers as a comma-separated list.) A = 3 5 8 0

User Jeri
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1 Answer

4 votes

Answer:


\lambda=8,\ \lambda=-5

Explanation:

Eigenvalues of a Matrix

Given a matrix A, the eigenvalues of A, called
\lambda are scalars who comply with the relation:


det(A-\lambda I)=0

Where I is the identity matrix


I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix is given as


A=\left[\begin{array}{cc}3&5\\8&0\end{array}\right]

Set up the equation to solve


det\left(\left[\begin{array}{cc}3&5\\8&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda \end{array}\right]\right)=0

Expanding the determinant


det\left(\left[\begin{array}{cc}3-\lambda&5\\8&-\lambda\end{array}\right]\right)=0


(3-\lambda)(-\lambda)-40=0

Operating Rearranging


\lambda^2-3\lambda-40=0

Factoring


(\lambda-8)(\lambda+5)=0

Solving, we have the eigenvalues


\boxed{\lambda=8,\ \lambda=-5}

User DrXCheng
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