How do you solve 5y+1=10y^2

asked Mar 11, 2021 33.6k views

1 vote

by Hilo

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$5y+1=10y^2\\10y^2-5y-1=0\\D=(-5)^2-4*10*(-1)=25+40=65=√(65)^2 \\y_1=(5+√(65) )/(20) \\y_2=(5-√(65) )/(20)$

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P.S. Hello from Russia :^)

Alan Whitelaw answered Mar 15, 2021

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