Question

What volume of neon gas occupies a container if 322 grams of neon is at 0.955 atm and -28.0 degrees Celsius?

Answer 1

The volume occupies of neon gas is 335, 7 L

Step-by-step explanation:

We use the formula PV=nRT. We convert the unit temperature Celsius into Kelvin: 0°C=273 K---> -28°C= -28+273= 245K. We calculate the number of mols in 322 grams of neon:

20,18 g---1 mol neon

322g---x= (322g x 1 mol neon)/ 20, 18g=15, 96 mol neon

PV=nRT ----> V= (nRT)/P

V= (15,96 mol x 0,082 l atm/K mol x 245 K)/ 0,955 atm= 335, 7 L