Question

Two charged particles are separated by a distance of .99m. If the charge on particle one is .00045C and the charge on particle two is .0000032C. What is the amount of force between them?

Answer 1

The force between the two charges will be 13.22N.

Step-by-step explanation:

The force between the two charges is given by Coulombs law which says

`F = k(Q_1Q_2)/(R^2).`

In our case

`Q_1= 0.00045C`,

`Q_2 = 0.0000032C`,

`R = 0.99m`.

therefore,

`F = (9*10^9)((0.00045C)(0.0000032C))/((0.99m)^2).`

`\boxed{F=13.22N}`

Hence, the force between the two charges will be 13.22N.