With which values ​​of the argument the function acquires a value equal to144 y = \frac{1}{9x {}^(2) } ​

Question

With which values ​​of the argument the function acquires a value equal to144


`y = \frac{1}{9x {}^(2) }`
​

Answer 1

Explanation:

hello :

solve : 1/9x² = 144

x² = 144×9

x² =(12×3)² means : x² =36²

so : x=36 or x= -36

Answer 2

`x=(1)/(36) \, \,and\,\, x=-(1)/(36)`

Explanation:

To find at which values of the argument the function renders 144, we need to solve for "x" in the equation when y is 144:

`y=(1)/(9\,x^2)\\144=(1)/(9\,x^2)\\144\,x^2=(1)/(9) \\x^2=(1)/(9\,(144)) \\x^2=(1)/(1296) \\x=+/-\sqrt{(1)/(1296) } \\x=+/-(1)/(36)`

Therefore there are two solutions: one is 1/36 and the other one is its opposite; -1/36