Question

the length of a rectangle is six times it’s width. If the perimeter of the rectangle is 112 yards, find it’s length and width.

Answer 1

The length of rectangle is 48 yards and width of the rectangle is 8 yards, if the perimeter of the rectangle is 112 yards.

Explanation:

The given is,

The perimeter of the rectangle is 112 yards

The length of a rectangle is six times it's width

Step:1

Let, p - Perimeter of the rectangle

l - Length of the rectangle

w - Width of the rectangle

Step:2

Formula for perimeter of rectangle,

`Perimeter, p = 2(l+w)`............................(1)

From given,

p = 112 yards

l = 6w ( ∵ From given)

w = w

Substitute the values,

112 = 2 ( 6w + w )

112 = 2 ( 7w )

112 = 14w

w = 8 yards

From the w value, l becomes

l = 6w

l = 6 × 8

l = 48 yards

Result:

The length of rectangle is 48 yards and width of the rectangle is 8 yards, if the perimeter of the rectangle is 112 yards.