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two point charges having charge values of 9.2 E -6 C and 3.5 E -6 C, respectively, are separated by 3 E -2 m. What is the absolute value of the mutual force between them

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Answer: The absolute value of the mutual force between the two point charges is 5.3952 x 10^-3 N.

Step-by-step explanation:

The mutual force between two point charges can be calculated using Coulomb's law, which states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them:

F = k * (q1 * q2) / r^2

where F is the force, k is Coulomb's constant (9.0 x 10^9 N m^2/C^2), q1 and q2 are the charges of the two-point charges, and r is the distance between them.

In this problem, q1 = 9.2 E-6 C, q2 = 3.5 E-6 C, and r = 3 E-2 m. Substituting these values into Coulomb's law, we get:

F = (9.0 x 10^9 N m^2/C^2) * [(9.2 E-6 C) * (3.5 E-6 C)] / (3 E-2 m)^2

F = 5.3952 x 10^-3 N

The absolute value of the mutual force between the two point charges is 5.3952 x 10^-3 N.

User Glebcom
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2 votes

Answer:

14

Step-by-step explanation:

User Reavis
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4.4k points