Question

3350 J of heat is required to raise the temperature of a sample of AlF3 from 250C to 800C. What is the mass of the sample?

I just want to know how to work this out. Please help me.

Answer 1

1. Look up the specific heat capacity of AlF₃
2. Calculate ΔT
3. Calculate the mass of AlF₃

Step-by-step explanation:

The formula for for the heat (q) absorbed by an object is

q = mCΔT, where

m = the mass of the sample

C = the specific heat capacity of the sample. and

ΔT = the change in temperature

1. What you must do

• Look up the specific heat capacity of AlF₃
• Calculate ΔT
• Calculate the mass of AlF₃

2. Sample calculation

For this example, I assume that the specific heat capacity of AlF₃ is 1.16 J·K⁻¹mol⁻¹ .

(a) Calculate ΔT

`\Delta T = T_{\text{f}} - T_{\text{i}} = 800 \, ^(\circ)\text{C} -250 \, ^(\circ)\text{C} = 550 \, ^(\circ)\text{C}`

(b) Calculate m

`\begin{array}{rcl}\text{3350 J} & = & m * 1.16 \text{ J}\cdot\text{K}^(-1) \text{mol}^(-1)* \text{550 K}\\3350 & = & m * \text{638 g}^(-1)\\m & = &\frac{3350}{\text{638 g}^(-1)}\\\\ & = & \text{ 5.2 g}\\\end{array}\\`