Question

what is the resistance of a 20.0 meter long tungsten rod with a cross sectional area of 1.00 times 10^-4 meter^2 at 20C

Answer 1

`0.0112 \Omega`

Step-by-step explanation:

The resistance of an object tells us how much the object opposes to the flow of current through it.

The resistance of a conductor is given by the formula

`R=(\rho L)/(A)`

where

`\rho` is the resistivity of the material

L is the length of the conductor

A is the cross-sectional area

For the tungsten rod in this problem, we have:

L = 20.0 m is the length

`A=1.00\cdot 10^(-4)m^2` is the cross-sectional area

`\rho=5.6\cdot 10^(-8) \Omega \cdot m` is the resistivity of tungsten at 20C

Substituting into the formula, we find the resistance of the tungsten rod:

`R=((5.6\cdot 10^(-8))(20.0))/(1.00\cdot 10^(-4))=0.0112 \Omega`