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16.4 mL of 0.135 M NaOH is used to neutralize 46.9 mL of HCl. The concentration of the HCl solution is ____ M (3 decimal places).

User Ij
by
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1 Answer

1 vote

The concentration of the HCl solution is 0.047 M.

Step-by-step explanation:

Data given about acid and base:

volume of acid Vacid = 46.9 ml

molarity of acid =?

volume of the base (NaOH) = 16.4 ml

molarity of the base = 0.135 M

To know the concentration of the acid in this reaction, the formula used in titration is used. It is

Macid X Vacid = Mbase X Vbase

the formula is rewritten as:

Macid =
(Mbase X Vbase)/(Vacid)

putting the values in the equation:

Macid =
(0.135 X 16.4)/(46.9)

= 0.047 M

the concentration of the acid i.e HCl in the solution is of 0.047 M.

User Tony DeStefano
by
7.3k points
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