Can someone explain what you do here!! Kind of low on time!!

Question

asked Feb 10, 2021 27.7k views

1 Answer

Manfred Weis · Answer 1 · 2021-02-16T21:38:43+0000

Answer:

a:

$sin(\theta)=(opposite)/(hypotenus)$

$sin(60)= (a)/(4\sqrt3)$

$(4\sqrt3)sin(60)= a$

$(4\sqrt3)((\sqrt3)/(2))= a$

6= a

b:

the answer choices all have the same value for b, so I dont have to solve for b at all.

$b=6\sqrt2$

c:

$cos(\theta)=(adjacent)/(hypotenus)$

$cos(60)= (c)/(4\sqrt3)$

$(4\sqrt3)cos(60)= c$

$(4\sqrt3)(1/2)= c$

$2\sqrt3= c$

d:

d is inside a 45-45-90 triangle. Therefore, side a and d must be of the same length.

d=a

d=6