205k views
3 votes
Please provide an explanation and steps

Please provide an explanation and steps-example-1
User Wangf
by
7.6k points

1 Answer

3 votes

Haven't done one of these in forever. We avoid the quotient rule with an implicit logarithmic differentiation.


y=((x^2+x+1)(x^3+2x+5))/((2x-1)^5)


\ln y = \ln(x^2+x+1) + \ln(x^3+2x+5) - 5\ln(2x-1)

Taking derivatives with respect to x,


y'/y = (2x+1)/(x^2+x+1) + (3x^2+2)/(x^3+2x+5) - (10)/(2x-1)


y' = y \left( (2x+1)/(x^2+x+1) + (3x^2+2)/(x^3+2x+5) - (10)/(2x-1) \right)


y' = ((x^2+x+1)(x^3+2x+5)(2x-1))/((2x-1)^6) \left( (2x+1)/(x^2+x+1) + (3x^2+2)/(x^3+2x+5) - (10)/(2x-1) \right)


y'(2x-1)^6 =(2x+1)(x^3+2x+5)(2x-1)+(3x^2+2)(x^2+x+1)(2x-1) \\\quad -10(x^2+x+1)(x^3+2x+5)


y'=(-7 x^4 - 16 x^3 - 51 x^2 - 70 x - 57)/((2x-1)^6)

User Estella
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories