Question

A balloon with a charge of 6.0 μC is held a distance of 0.80 m from a second balloon having the same charge. Calculate the magnitude of the repulsive force.

Answer 1

Answer:0.506 N

Step-by-step explanation:

Given

Charge on first balloon
`q_1=6\ \mu C`

Charge on second balloon is
`q_2=6\ \mu C`

Distance between them
`r=0.8\ m`

Electrostatic Repulsive force is given by

`F=(kq_1q_2)/(r^2)`

Where K is constant

`F=(9* 10^9* 6* 10^(-6)* 6* 10^(-6))/((0.8)^2)`

`F=(324* 10^(-3))/(0.64)`

`F=0.506\ N`