Question

An ideal gas occupies a volume of 0.60 m^3 at 5.0 ATM and 400. K. What volume does it occupy at 4.0 ATM and a temperature of 200. K?

Answer 1

Answer:0.375m3

Explanation:This is general gas law. The expression is given by P1V1/T1 =P2V2/T2

we are looking for V2 so let's make it the change of subject of formula

V2= P1xV1xT2/P2T1

= 5 x 0.6 x 200/400 x 4

= 0.375m3