Question

A 21.6 ml ball has a pressure of 879.3 torr at 331 K. If the temperatire spikes 410 K and the pressure increases to 956.2 torr what is the volume of the bal

Answer 1

24.6 mL is the volume of the ball when the temperature spikes 410 K and the pressure increases to 956.2 Torr

Step-by-step explanation:

The combined gas equation is,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1` = initial pressure inside a ball = 879.3 Torr

`P_2` = final pressure inside a ball = 956.2 Torr

`V_1` = initial volume of ball =
`21.6 mL`

`V_2` = final volume of gas = ?

`T_1` = initial temperature of gas =
`331 K`

`T_2` = final temperature of gas =
`410 K`

Now put all the given values in the above equation, we get:

`(879.3 Torr * 21.6 mL)/(331 K)=(956.2 Torr* V_2)/(410 K)`

`V_2=24.6 mL`

24.6 mL is the volume of the ball when the temperature spikes 410 K and the pressure increases to 956.2 Torr