Question

If you see this PLEASE HELP

Answer 1

Given:

`1. -3 x^(2)\left(4 x^(3)-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^(2)+5 x-2\right)$`

To find:

The product of the polynomials.

Solution:

1.
`-3 x^(2)\left(4 x^(3)-7\right)`
`=-3 x^(2)(4 x^(3)) -3 x^(2)(-7)`

Multiply the numerical coefficient and add the powers of x.

`=-12 x^(5)+21 x^(2)`

2.
`(6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)`

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

`=12 x^2+18x-10 x-15`

`=12 x^2+8x-15`

3.
`(3 x-1)\left(x^(2)+5 x-2\right)=3 x(x^(2)+5 x-2)-1(x^(2)+5 x-2)`

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

`=3x^(3)+15 x^2-6x-x^(2)-5 x+2`

Add or subtract like terms together.

`=3x^(3)+14 x^2-11x+2`

The answer for multiplying polynomials:

`1. -12 x^(5)+21 x^(2)`

`2. \ 12 x^2+8x-15`

`3. \ 3x^(3)+14 x^2-11x+2`