Question

The volume of a certain gas is 29.3 liters at STP. What would be the volume of the same gas at 1.39 atmospheres and -23.00C? (R=0.0821 L-atm/mol.k)

19.3L
22.4L
23.0L
37.31

Answer 1

19.32L

Step-by-step explanation:

Given parameters:

Volume of the gas at STP = 29.3liters;

Using this information first, let us find the number of moles of the gas.

Number of moles =
`(volume of gas)/(22.4)`

With the number of moles, we can further solve this problem;

Number of moles =
`(29.3)/(22.4)` = 1.31 moles

More parameters;

Pressure on gas = 1.39atm

temperature = -23°C = -23 + 273 = 250K

Unknown:

Volume of gas = ?

Solution:

The ideal gas equation is the perfect fix to solve this problem.

It is mathematically expressed as;

Pv = nRT

where P is the pressure

v is the volume

R is the gas constant

n is the number of moles

T is the temperature

Input the parameters;

1.39 x V = 1.31 x 0.082 x 250

V = 19.32L