Question

Teri begins walking at 2 miles per hour at 1:00 P.M. If Cindy leaves from the same point 30 minutes later walking at 3 miles per hour, when will she catch Teri

Answer 1

Therefore Cindy will catch Teri after 1 hour when she starts to walk.

Explanation:

Assume after x hour Cindy will catch Teri.

Given that, Teri begins walking at 2 miles per hour at 1:00 pm.

Teri walks 30 minutes = 0.5 hour more than Cindy.

Teri walks (x+.5) hours.

We know that,

`Distance=Time * Speed`

The distance covered by Teri in (x+.5) hours is
`2 (x+.5)` miles.

The walking speed of Cindy is 3 miles per hour.

The distance covered by Cindy in x hours is
`(3* x)` = 3x miles.

Cindy and Teri both meet at a point. So both will walk same distance.

According to the problem,

`2 (x+.5)=3x`

`\Rightarrow 2x+1=3x`

`\Rightarrow x=1`

Therefore Cindy will catch Teri after 1 hour when she starts to walk.