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You need to reverse the symbol to solve which inequality?

A) 4(5-y) greater than or equal to 80
B) 2(y-3) greater than or equal to 8
C) 3y - 4, >1
D -3/4 + 6y > 1/4

User Jeff Maes
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1 Answer

6 votes

When you multiply/divide by a negative number while solving the inequality, you reverse the symbol.

A.) 4(5 - y) ≥ 80 To solve this, isolate/get the variable "y" by itself in the inequality. Divide 4 on both sides


(4(5-y))/(4) \geq (80)/(4)

5 - y ≥ 20 Subtract 5 on both sides

5 - 5 - y ≥ 20 - 5

-y ≥ 15 Divide -1 on both sides to get "y" by itself


(-y)/(-1) \geq (15)/(-1) Because you are dividing by a negative number, you need to reverse the sign

y ≤ -15

B.) 2(y - 3) ≥ 8 Isolate "y", divide 2 on both sides

y - 3 ≥ 4 Add 3 on both sides to get "y" by itself

y ≥ 7

C.) 3y - 4 > 1 Add 4 on both sides

3y > 1 Divide 3 on both sides to get "y" by itself


y>(1)/(3)

D.)
-(3)/(4) +6y > (1)/(4) Isolate "y", add 3/4 on both sides

6y > 1 Divide 6 on both sides to get "y" by itseld


y>(1)/(6)