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14) A barking dog delivers about 1 mW of power, which is assumed to be uniformly distributed in all directions. What is the intensity level at a distance 5.00 m from the dog?

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Answer:

Intensity of sound is given as


I = 3.18 * 10^(-6) W/m^2

Step-by-step explanation:

As we know that the intensity of the sound is defined as power received per unit area

So here we know that dog delivers total power

P = 1 mW

now it delivers it into spherical area of radius r = 5 m

now we have


I = (P)/(4\pi r^2)

so we have


I = (1* 10^(-3))/(4\pi(5^2))


I = 3.18 * 10^(-6) W/m^2

User Erling Olsen
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