Question

What is the equation of a line that passes through the points (3, 6) and (8, 4) in slope intercept form?

Answer 1

`y=-(2)/(5)x +8.4`

Explanation:

Gradient

`m =(y-y1)/(x-x1)`

`m = (6-4)/(3-8)`

`m=-(2)/(5)`

Equation of a line

`(y-y1)=m(x-x1)\\`

- Sub one set of points into equation

`(y-6)= -(2)/(5) (x-6)`

`y=-(2)/(5)x +8.4`