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What are the solutions to the equation x2 +2x-8=0

User Pwnrar
by
7.6k points

2 Answers

3 votes

Answer:


x = -4, x = 2

Explanation:

Step 1: Factor


x^2 + 2x - 8 = 0


x^2 + 4x - 2x - 8 = 0


(x + 4)(x - 2) = 0

Step 2: Find the zeros


x + 4 - 4 = 0 - 4


x = -4


x - 2 + 2 = 0 + 2


x = 2

Answer:
x = -4, x = 2

User Brian Ocampo
by
7.9k points
3 votes

Answer:

x=2 x=-4

Explanation:

x^2 +2x-8=0

Factor

What numbers multiply to -8 and add to 2

-2*4 = -8

-2+4 =2

(x-2) (x+4) =0

Using the zero product property

x-2 =0 x+4 =0

x-2+2=0+2 x+4-4=0-4

x=2 x=-4

User Cedekasme
by
8.7k points

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