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5y+2(3y-1)=1y-(y+2)=

5y+2(3y-1)=1y-(y+2)=
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5y+2(3y-1)=1y-(y+2)=

User Pbialy
by
8.2k points

1 Answer

3 votes

Answer:

y=0

Explanation:

5y+2(3y-1)=1y-(y+2)

Distribute

5y +6y -2 = y -y -2

Combine like terms

11y -2 = -2

Add 2 to each side

11y -2+2 = -2+2

11y =0

Divide by 11

11y/11 =0/11

y =0

User Bart Czernicki
by
7.9k points
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